Продольные колебания пакета стержней - page 5

AU,
ˉ
V
H
=
l
0
Z
0
m
0
(
x
)
1
m
0
(
x
)
∂x
EF
0
(
x
)
∂u
0
(
x
)
∂x
ˉ
v
0
(
x
)
dx
+
+
N
X
j
=1
l
j
Z
0
m
j
(
x
)
1
m
j
(
x
)
∂x
EF
j
(
x
)
∂u
j
(
x
)
∂x
ˉ
v
j
(
x
)
dx
=
. . .
=
=
l
0
Z
0
EF
0
(
x
)
u
0
0
(
x
) ˉ
v
0
0
(
x
)
dx
EF
0
(
x
)
u
0
0
(
x
) ˉ
v
0
(
x
)
l
0
0
+
+
l
0
Z
l
+0
EF
0
(
x
)
u
0
0
(
x
) ˉ
v
0
0
(
x
)
dx
EF
0
(
x
)
u
0
0
(
x
) ˉ
v
0
(
x
)
l
0
l
+0
+
+
N
X
j
=1
l
j
Z
0
EF
j
(
x
)
u
0
j
(
x
) ˉ
v
0
0
(
x
)
dx
N
X
j
=1
EF
j
(
x
)
u
0
j
(
x
) ˉ
v
j
(
x
)
l
j
0
=
=
l
0
Z
0
EF
0
(
x
)
u
0
0
(
x
) ˉ
v
0
0
(
x
)
dx
EF
0
(
x
A
0)
u
0
0
(
x
A
0) ˉ
v
0
(
x
A
) +
+
EF
0
(
x
A
+ 0)
u
0
0
(
x
A
+ 0) ˉ
v
0
(
x
A
)
N
X
j
=1
EF
j
(
l
j
)
u
0
j
(
l
j
) ˉ
v
j
(
l
j
) +
+
N
X
j
=1
l
j
Z
0
EF
j
(
x
)
u
0
j
(
x
) ˉ
v
0
j
(
x
)
dx
=
l
0
Z
0
EF
0
(
x
)
u
0
0
(
x
) ˉ
v
0
0
(
x
)
dx
+
+
N
X
j
=1
l
j
Z
0
EF
j
(
x
)
u
0
j
(
x
) ˉ
v
0
j
(
x
)
dx
+
v
0
(
x
A
) [
EF
0
(
x
A
+ 0)
u
0
0
(
x
A
+ 0)
EF
0
(
x
A
0)
u
0
0
(
x
A
0)]
N
X
j
=1
EF
j
(
l
j
)
u
0
j
(
l
j
) ˉ
v
0
j
(
l
j
) =
l
0
Z
0
EF
0
(
x
)
u
0
0
(
x
) ˉ
v
0
0
(
x
)
dx
+
+
N
X
j
=1
l
j
Z
0
EF
j
(
x
)
u
0
j
(
x
) ˉ
v
0
j
(
x
)
dx
+
+
N
X
j
=1
k
(
u
0
(
x
A
)
u
j
(
l
j
)) (ˉ
v
0
(
x
A
)
ˉ
v
j
(
l
j
)) =
U, A
ˉ
V
H
;
ISSN 1812-3368. Вестник МГТУ им. Н.Э. Баумана. Сер. “Естественные науки”. 2014. № 6
57
1,2,3,4 6,7,8,9,10,11,12,13,14
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